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#1 Re: Help Me ! » Circular Functions!!! » 2006-03-05 09:27:24

help me please...this is urgent guys...huhuhu

#2 Help Me ! » Circular Functions!!! » 2006-03-05 08:46:39

katy
Replies: 3

I am stuck with this one...can anyone please show me how to do this step by step please...

The proplem is:
sin 2x=1/2

and the answers are:
2x=30degrees,150degrees,390degrees,410degrees
  x=15degrees,75degrees,195degrees,205degrees


how do you know to do this??...

#3 Help Me ! » help me please.! » 2006-01-22 06:28:49

katy
Replies: 4

I need help with these problems:

#1) For which set of data would 2 triangles be formed?(for these questions please show me how do you know the answers please...?)
a) <B=34degrees, a=4, b=5
b) <B=34degrees, a=4, b=2
c) <B=34degrees, a=4, b=2.237
d) <B=34degrees, a=4, b=3


#2) The sum of the roots of -5x^2+7x-2=0 is
a) 7/-5
b) 7/5
c) 2/5
d) 2/-7


#3) If a quadratic equation has 2 irrational solutions, then its discriminant could equal
a) 15
b) 0
c) -16
d) 49
e) -1

#4 Help Me ! » Can anyone show me how to graph this please... » 2006-01-21 09:11:27

katy
Replies: 3

How can you change this to descriptive form, graph it and state the Domain, HA(Asymptote), Y-intercept and X-intercept??Please give me a tutorial!

y=(3x+2)/(x+1)


thanks a lot.....:o

#5 Help Me ! » I need help with this problem please!! » 2006-01-21 04:53:08

katy
Replies: 11

Hi...I have a problem that really needs to be solved for my study for the exam please.(it is grade 11 problem.)

1) a) If <C=40degrees, c=35 and b=40 in triangle ABC, then determine the number of triangles that would be possible with these values. Justify your answer by showing your work.
    b) Based on your answer to part 1a), solve for <B in your triangle(s).

Many thanks to you guys..!!:P;)

#6 Help Me ! » Factor Theorem? » 2005-12-30 06:03:19

katy
Replies: 14

I am stuck with this peoblem...someone please help!!

Completely factor (x^3+3x^2+13x-15) using the factor theorem.

#7 Re: Help Me ! » I need help with these problems please.. » 2005-12-29 11:10:01

mikau wrote:

Nah we just pretend to be.

lol...of course you all are....I am the stupid one..hehehe

#8 Help Me ! » Inverse Functions!?? » 2005-12-29 11:06:37

katy
Replies: 6

hi..I need help with these two questions from my Review Sheet...

1)What are two different ways one could determine if one function is the inverse of another?Give an example of each way.

2)Explain why the inverse of a quadratic function is not a function?What do we do to ensure that the inverse of a quadratic is a function?Give an example.


thanks in advance...

#9 Re: Help Me ! » I need help with these problems please.. » 2005-12-29 10:21:51

thanks a lot guys...i get them now...you all are smart.
katy.

#10 Re: Help Me ! » I need help with these problems please.. » 2005-12-29 07:44:09

thanks a lot guys....
I have one more question:
1)Explain when a parabola will have 2 real roots, 2 imaginary roots, and 2 equal real roots.Explain what characteristics the discriminant will have for the above cases
My answer is:
discriminant>0 (2 real roots)
discriminant<0(2 imaginary roots)
discriminant=0(2 equal real roots)
is it right?

#11 Help Me ! » I need help with these problems please.. » 2005-12-29 06:24:25

katy
Replies: 15

I am doing some math problems and these are the ones I can not solve..:

1)The sum of 2 numbers is 34.Find the numbers if the sum of their squares is a minimum.
2)Without solving the equation find the discriminant and state the nature of the roots: 2x^2+3x-10
(in question #2 how can you find the discriminant and state the nature of the roots just by looking???)

Many thanks to the people who can help me with this......

Katy

#12 Maths Teaching Resources » I am looking for some websites about Rational Functions. » 2005-12-28 11:10:13

katy
Replies: 1

I am new to Rational Functions.I really need any website which teaches some basic about Rational Functions...(ex:graphing them,state vertical and horizontal asymptotes and domain and range...) somthing like that....
thanks in advance!

#13 Re: Help Me ! » High School Student needs your help please... » 2005-12-28 10:41:34

mikau wrote:

Well basicly its the same problem presented in two different forms. When you graph an equation or a function on a cartesian coordinate grid, the horizontal location on the x axis represents the value of what they call the independant variable. The height on the y axis represents the value of the expression evaluated at that location.

Therefore if you have the eqaution:

L - S = 10

And

S * L = Product

We can rearrange the first equation to find L = 10 + S and subsitute this expression for L:

S * (10 + S) = Product

10S + S^2 = Product

if we graph were to replace S with x and Product with Y we would have:

x^2 + 10x = y

this is the eqaution of a parabolla. This graph represents the product of the two numbers who's difference is 10. Therefore we can look at the low point on the graph to find the minimum product, and note what value of x is required. We used x to represent S so we can use the x coordinate of the lowpoint on the graph for S, and the solve for L. The equation y = x^2 + 10x is a parabolla that opens upward, thus the vertex is the lowpoint on the graph. Using any of the various methods to find the vertex, we find the x coordinate of the vertex is x = -5. We used  x to represent S so S = -5

Now lets use this value of S in the original equation to find L.

L - S = 10

L - (-5) = 10

L + 5 = 10

L = 5

So the two numbers are 5 and -5. :-)

thank you so much for taking your time to help me solve the problems....this is extremely helpful to me....:-)

#14 Help Me ! » High School Student needs your help please... » 2005-12-28 05:48:29

katy
Replies: 7

hi everyone,I am a high school student and my exam is coming up around two weeks and I really need your help please....here are 2 math problems I really need answers...if anyone of you can solve any of them then I am really more than happy...
1)Find the equation of a parabola with vertex (-4,-1) and y-intercept -5
2)Find two numbers whose difference is 10 and whose product is a minimum

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