Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

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bobbym wrote:

What name would you use for 14?

n872yt3r

bobbym wrote:

Then aren't you done at 12? We have used all 6 names up!

No.I am talking that at somewhere near infinity (like that: )

9,xxx,xxx,xxx,xxx,xxx,xxx,xxx

bobbym <-respective number

anonimnystefy

n872yt3r

Agnishom

bobbym wrote:

Let's see if I can understand what you want. Do you just want to use those 6 members names?

Yes.

bobbym wrote:

What limit? We only have 185000 members?

I mean that the limit that the members who played that game must post member name's after how much posts?

bobbym wrote:

Hi auyeungyat;

I am not following you. What is the question?

The limit that all player of this game must(follow rules)post a username.

**auyeungyat**- Replies: 17

Hello Everybody,

This is a infinity game and the interest of it is in the 'Infinity'.

Anybody knows the limit of this game?take"Add 1, then say a username"as an example.

(Because the spam filter don't let me send links,I should post the rules here.Sorry for the inconvenience.

So, if it is a multiple of 3, say bobbym.

If multiple of 5, say anonimnystefy.

If multiple of 7, say n872yt3r.

If multiple of 11, say Agnishom.

If a multiple of 13, say Nehushtan if you are a boy.

If a girl, say mathgogocart.

Example :

1

2

bobbym

4

anonimnystefy

6

n872yt3r

8

9

10

Agnishom

12

Nehushtan)

So,How can I calculate the final limit(means that everybody need to speak a username)?

Using a real time chattting&face-timing software might help you better!

So,WHO IS RIGHT!!!

**EXECUTE**

DO(to execute=to do)

RESEARCH(Do something need to research)

VIEW(view documents=research something)**VIEWED**(past tense of view)

1.P=[1/6(six)x5/6(not six)x5/6(not six)=**25/216**]

According to your message,2 should be P=[1-[answer 1]] ,so your answer is P=[1-25/216=**191/216**].

Can you think that **191/216** is right?

My answer is:

A:P=[1/6(six)x5/6(not six)x5/6(not six)=**25/216**]

B:P=[1/6(six)x1/6(six)x1(no six=5/6,six=1/6(*It can be a six because the question b need two sixes,so three is acceptable*)5/6+1/6=1)=**1/36**]

Very...Brain-strechting...**DUE**

TIME

CLOCK**FIX**

yes,I want a Terminal code.Thank you!

**auyeungyat**- Replies: 2

I got stuck in thinking the infinity.

I thought like this:

Let infinity be x

2x=2 infinity

The main problem is:There isn't 2 times infinity!

How can it be proven?

I have tested on my computer(Mac on Terminal).That doesn't generate any numbers!

**auyeungyat**- Replies: 3

You pick a number(3 numbers),multiply by 7,11,13,(example:123X7X11X13=123123)

How it comes?

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