This is a infinity game and the interest of it is in the 'Infinity'.
Anybody knows the limit of this game?take"Add 1, then say a username"as an example.
(Because the spam filter don't let me send links,I should post the rules here.Sorry for the inconvenience.
So, if it is a multiple of 3, say bobbym.
If multiple of 5, say anonimnystefy.
If multiple of 7, say n872yt3r.
If multiple of 11, say Agnishom.
If a multiple of 13, say Nehushtan if you are a boy.
If a girl, say mathgogocart.
So,How can I calculate the final limit(means that everybody need to speak a username)?
It is wrong because
1.P=[1/6(six)x5/6(not six)x5/6(not six)=25/216]
According to your message,2 should be P=[1-[answer 1]] ,so your answer is P=[1-25/216=191/216].
Can you think that 191/216 is right?
My answer is:
A:P=[1/6(six)x5/6(not six)x5/6(not six)=25/216]
B:P=[1/6(six)x1/6(six)x1(no six=5/6,six=1/6(It can be a six because the question b need two sixes,so three is acceptable)5/6+1/6=1)=1/36]