Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

The average test mark for a class of 21 students is 65. Peter's mark was recorded as 35 instead of 55. What is the correct average mark for the test?

I had 62.8571 as answer, is that correct?

**EbenezerSon**- Replies: 3

I'm a little bit bemused about the difference between grouped and ungrouped data.

Does a grouped data always have class intervals such as 0-9, 10-19...? Whiles an ungrouped data does not have such class intervals?

Please confirm, thank you in advance

**EbenezerSon**- Replies: 2

Hi,

How can one calculate for the one-tenth of $3200?

Thank you

Many thank Bob, but see this;

(1) A rectangular garden has 24m fence surrounding its. Find the dimension of the plot if its area is 27m^2.

I have dealt with it and I had 3 as width and 9 as the lenght, please confirm-

Thank you.

Then please, check for me;

If issosceles then;

2x = 180

x = 180/2

x = 90

Is both length calculations correct?

**EbenezerSon**- Replies: 5

Hi;

Please help me with this;

The area of a right angled triangle is 50cm^2. One of its angler is 45°. Find, correct to one decimal place, the length of the longest side(hypotenuse)

Many thanks

Hi; bob thank you - but are you using vector approach for this question?

Thank you

A cyclist starts a journey from town A. He rides 10km north, then 5km east and finally 10km on a bearing of 045.

(a) How far east is the cyclist's destination from town A?

(b) How far north is the cyclist's destination from A?

(C) Find the distance and bearing of the cyclist's destination from town A.

(Correct your answers to nearest kilometers and degree)

Is hard for me using vector approach

I started by saying

(10km, 000°) (5km, 000°) (10km, 045°) I used Zero degrees for the unknown degrees.

(10cos000° and 10sin000°) =(10*cos90 and 10*sin 90) = (0 And 10) I did the same for the rest.

Thank you. I will put a bearing question here which I think cannot be solved by vector appraoch. As far as I remember, Bob bundy made it clear to me that not all bearing questions could be solved using vector approach, I wanted to know this truth from different perspective. Thanks once more!

Pece kololo!

**EbenezerSon**- Replies: 8

Hi,

Please, I wanted to know if all bearing problems could be solved by using vector approach method. Please confirm

Many thanks!

**EbenezerSon**- Replies: 2

Hi;

I am having problems getting the answer;

An arc substends angle of 60° of the centre of a circle of radius 14cm.

(a) Find the perimeter of major sector

I had 76.67 as the answer but not sure - please confirm.

Many thanks!

Thanks Agnashom!

One question left and that is;

When one crosses diagonal lines within a rectangle which triangle is formed?

**EbenezerSon**- Replies: 3

Hi; I have some few questions to ask;

(1) Are the internal angles of rhombus, square, rectangle and parallelograms equals 360?

(2) When one makes diagonal angles within rhombus is the triangle formed be an isosceles or equilateral?

(3) When one crosses diagonal lines within a square, is the triangle formed be equilateral or isosceles?

Many thanks

I have made the amendment- thank you

I have bracket

Hi;

I am given it a try concerning the conversion;

Log x = 1/2log x

so, it will be

log (x) = 1/2log (x)

Is that correct?

Please, help.

I don't understand the question.

Show that

Log x = 1/2logx and hence solve log x + 1/2 = logx

In both cases the LHS is in base 4 and the RHS is in base 2

Thanks

This is it;

log(x^2 + 1) - 2logx = 1

bobbym wrote:

Ask the tutor to plug and check his answer.

Yes - have seen the tutor - the tutor gave me a calculator which I plugged 1/3 into the equation and I had 1(one), so it seems his answer is correct. What do you say Bobbym?

Ok. Let me put this

Log(x-3) - logx = 2.

Is negative one (-1) the correct answer?

Good!

Thanks bobym - I will post problems.

Big thanks!

Again;

x = 10/log16

correct?