A cyclist starts a journey from town A. He rides 10km north, then 5km east and finally 10km on a bearing of 045.
(a) How far east is the cyclist's destination from town A?
(b) How far north is the cyclist's destination from A?
(C) Find the distance and bearing of the cyclist's destination from town A.
(Correct your answers to nearest kilometers and degree)
Is hard for me using vector approach
I started by saying
(10km, 000°) (5km, 000°) (10km, 045°) I used Zero degrees for the unknown degrees.
(10cos000° and 10sin000°) =(10*cos90 and 10*sin 90) = (0 And 10) I did the same for the rest.
Thank you. I will put a bearing question here which I think cannot be solved by vector appraoch. As far as I remember, Bob bundy made it clear to me that not all bearing questions could be solved using vector approach, I wanted to know this truth from different perspective. Thanks once more!
Hi; I have some few questions to ask;
(1) Are the internal angles of rhombus, square, rectangle and parallelograms equals 360?
(2) When one makes diagonal angles within rhombus is the triangle formed be an isosceles or equilateral?
(3) When one crosses diagonal lines within a square, is the triangle formed be equilateral or isosceles?