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#1 Re: Help Me ! » About square, rhombus, rectangle and parallelograms » 2015-02-19 08:16:05

Thanks Agnashom!

One question left and that is;

When one crosses diagonal lines within a rectangle which triangle is formed?

#2 Help Me ! » About square, rhombus, rectangle and parallelograms » 2015-02-19 05:29:03

EbenezerSon
Replies: 3

Hi; I have some few questions to ask;

(1) Are the internal angles of rhombus, square, rectangle and parallelograms equals 360?

(2) When one makes diagonal angles within rhombus is the triangle formed be an isosceles or equilateral?

(3) When one crosses diagonal lines within a square, is the triangle formed be equilateral or isosceles?

Many thanks

#3 Re: Help Me ! » Simplify the following: » 2014-12-03 02:38:52

I have made the amendment- thank you

#5 Re: Help Me ! » Simplify the following: » 2014-12-01 21:08:01

Hi;

I am given it a try concerning the conversion;

Log x = 1/2log x

so, it will be
log (x) = 1/2log (x)

Is that correct?

#6 Re: Help Me ! » Simplify the following: » 2014-12-01 06:38:30

Please, help.

I don't understand the question.

#7 Re: Help Me ! » Simplify the following: » 2014-12-01 06:24:24

Show that
Log x = 1/2logx and hence solve log x + 1/2 = logx


In both cases the LHS is in base 4 and the RHS is in base 2


Thanks

#8 Re: Help Me ! » Simplify the following: » 2014-11-24 21:37:32

This is it;

log(x^2 + 1) - 2logx = 1

#9 Re: Help Me ! » Simplify the following: » 2014-11-24 21:22:41

bobbym wrote:

Ask the tutor to plug and check his answer.


Yes - have seen the tutor - the tutor gave me a calculator which I plugged 1/3 into the equation and I had 1(one),  so it seems his answer is correct. What do you say Bobbym?

#10 Re: Help Me ! » Simplify the following: » 2014-10-25 21:27:08

I have plug it in and the calculator gave me "math error". But I want to add that the base is five [5] for all.

#11 Re: Help Me ! » Simplify the following: » 2014-10-25 05:46:49

Ok. Let me put this

Log(x-3) - logx = 2.
Is negative one (-1) the correct answer?

#12 Re: Help Me ! » Simplify the following: » 2014-10-25 05:04:27

Good!
Thanks bobym - I will post problems.

Big thanks!

#16 Re: Help Me ! » Simplify the following: » 2014-10-25 04:26:23

xlog16 = log10
xlog16 = 1
x = 1/log16
Correct?

#17 Re: Help Me ! » Simplify the following: » 2014-10-25 04:17:20

Thanks! Bobbym

I am now getting logarithm better.
See;
solve for x in,  log16^x.

log16^x = 10
xlog16 = log10
x = log10/log16
correct?

#18 Re: Help Me ! » Simplify the following: » 2014-10-25 04:03:01

I think your methods  are good concerning the simplification of like terms in logs. Thanks for answering.

Look it if it is good
log16^-x = log2 + log7
-xlog16 = log14
  x= -log14/log16
Is it good?

#19 Re: Help Me ! » Simplify the following: » 2014-10-25 03:46:52

Still I haven't come across the tutor - but I will definitely meet him.

My one question is - when do one take antilogs of both sides of an equation?

#20 Re: Help Me ! » Simplify the following: » 2014-10-21 04:54:01

I am away from the tutor now - but I shall tell him later

#21 Re: Help Me ! » Simplify the following: » 2014-10-21 04:27:00

The book says - if the base is not written then it is base 10. And with this problem the base is not written - so it used base 10

#22 Re: Help Me ! » Simplify the following: » 2014-10-21 04:14:47

Wow!
I confronted a math tutor - but he claimed the answer 1/3 or -1/3 is correct - now I Could realise that your method is good. Please I want the tutor to see for himself your steps because he was insisting that the books' answer is correct

Thanks bobbym

#23 Re: Help Me ! » Simplify the following: » 2014-10-21 03:58:49

Yes that's the problem - I copied it correctly.

When you plug in your answers does it give 1?

#25 Re: Help Me ! » Simplify the following: » 2014-10-20 04:55:26

Hi, Bobbym, I was called away, I am sorry - but I don't have my calculator with me now.
It is negative or positive 1/3 in the book as an answer. When I get to  the house I will punch them in the calculator and see if it really gives negative or positive 1/3.

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