Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:58:03

thanks for sharing... smile i bet bobbym is a professor isn't he?

#2 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:49:07

totally agree with you dude... well i can't find the pdf file online any site where i can get it for free

#3 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:40:05

okay.... but it's a U.S. author i don't think i will find it in one of my nearby libraries... and agnishom.... u sure? i thought u r a professor... i mean how did u manage to go through all this content.... don't u read other subjects as well?

#4 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:35:35

big_smile you are right.... well thanks for the help guys.... looking forward to buy it... though it costs like 10 grand in rupees

#5 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:29:04

okay... well it says that the book is for B.Sc in math... i am kid in 12th grade... you think it's the right book for me?

#6 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:22:37

ok... well i read that it contains graph theory... why is that necessary for combinatorics?

#7 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:17:54

well does it cover the basic combinatorics as well... i think i will need to rebuild my basics to be able to fully appreciate it's applications

#8 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:13:40

that's it's name?  "tucker book" on google gave me links to amazon having weird books "they serve beer in hell"  tongue can you be more specific....

#9 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:10:00

big_smile so any suggestions for a good book that i can read for combinatorics... including such problems...

#10 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:07:59

36... the answer...

i bet you didn't expand that term by hand....

#11 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 06:05:27

okay so we now get to back the question that u originally asked me.... right... we now need to find the coefficient of x^10 in this expansion where the whole term is raised to 3....

now getting back to the multinomial theorem....(i have got a fair enough idea of binomial theorem and have read that multinomial theorem is general form of bi theo..)

#12 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:56:38

okay.... go on... i have the polynomials representing the variables...

#13 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:47:29

x can be any number from one to ten but why does it mean that it can be represented as x+x^2 and so on till x^10 ?

#14 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:42:26

oh wait... i can't... big_smile i got it... i can not put a dash at an end... that would mean that one of the groups (variable) is zero which is against my constraint... big_smile

#15 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:40:51

but there's this one problem how did u find that there are 9 spaces when u know that there are 10 x's.... you can put a dash in place of each x.. so there must be 10 spaces right? what  am i missing here....?

#16 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:39:08

well that's just choosing 2 spaces out of 9.... cool i got it it's (9 chooses 2)... brilliant...

#17 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:31:57

umm... take x_xxxxxx_xxx_xxx.... so there are groups (x) (xxxxxx) (xxx) (xxx)....  let a=(x) b=(xxxxxx) c=(xxx) d=(xxx)..

the sum of these groups or variables is 13. and i took the c and d as the same as there is no constraint like a,b,c,d are distinct....

#18 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:25:13

that's easy just take 13 x's in a line put 3 dashes in between them... it gives me 4 groups of  x's... well sum of groups in any such arrangement will give me 13... these groups are my variables a,b,c,d.... right...?

#19 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:15:43

the minimum value of any of the variables is 1 and maximum is 8 right.... so if i take x as say 1 then the rest of the two variables are to be selected from the remaining x's right?

#20 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:12:50

yeah... i get it.... so these variables (groups)

#21 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:08:01

sorry my bad... i was counting the dashes as well in my mind... anyways... the answer to this step is again 10... you mean that any such arrangement with two dashes has the sum of such groups equal to 10 right...

#22 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 05:03:15

you mean just add the 3+4+3? or like the total number or arrangements....
if the first thing is what ur asking me to do then it's 12

#23 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 04:58:08

they are greater then 3 but less then 4 in each group of x's @bobbym

#24 Re: Help Me ! » number of solutions to a linear equation » 2014-12-14 04:56:06

@agnishom no i don't but i have seen a formula related to that problem.... i just can't remember it...

Board footer

Powered by FluxBB