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  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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#1 Re: Help Me ! » probability question help me » 2013-03-23 23:13:58

I am trying to understand the logic behind the terms that's all.

Summation from j= 0 to n of (-1)^j/j! in the numerator is not getting into my head.

As far as my understanding goes, it computes the number of ways you can give out n names to n people without any of them having their own name.

Why do we need to multiply the summation in the numerator with P(no one getting drunk)?

#2 Re: Help Me ! » probability question help me » 2013-03-23 21:42:28

and why did we have to time that by (k-1)!?

#3 Re: Help Me ! » probability question help me » 2013-03-23 21:41:22

That is quite okay, thank you.
Although I do not understand the 2nd summation in the numerator. What does it compute? the probability that n people (who are gonna get drunk) don't have each other's name?

#5 Re: Help Me ! » probability question help me » 2013-03-23 20:55:58

Hi, sorry for bothering again, but what is j in this case?

#6 Re: Help Me ! » probability question help me » 2013-03-23 20:35:20

I think there's a gamma distribution in there? Unfortunately I haven't learned that yet. Would be okay if you rewrite the formula without the gamma distribution? thank you very much. smile

#7 Re: Help Me ! » probability question help me » 2013-03-23 20:17:51

bobbym wrote:

Hi;

If possible, can you please write this in a simplier format? as I don't quite understand these notations. Thank you very much. big_smile

#8 Re: Help Me ! » probability question help me » 2013-03-23 20:14:54

Hi, would you be able to show me the working for b, for the general formula of expected number of drunk please? thank you very much smile.

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