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**Primenumbers**- Replies: 3

Fermat's Last Theorem states that no three positive integers a, b, and c satisfy the equation

for any integer value of n strictly greater than two.Let

where n >2Then

must equal:must have opposite remainders for

Adding y to one and minusing y from another will keep them opposite if they are already opposite. So let's see if the two squares have opposite remainders for .

If we add them together they should=0 if they are opposite.

No!

Fermat's Last theorem is True.

I don't know, it's just a Maths degree, starting 2017. Doing Foundation Year and Placement Year.

Maths now.

I got into Uni to do maths! I am going to do that now.

Q: Why did the angry Jedi cross the road?

A: To get to the Dark Side.

No way! That's not awesome.

Thirty and counting!

Can be written as....

And we know

So,

569,673=(1x2)+(2x4)+(4x6)+(6x8)+(10x12)+(12x14)+(16x18).

Well usually you'd do

where x=(2-1)(3-1)(5-1)(7-1) and it would be factorable by 2,3,5,7........But if you use a composite Ie. it won't be factorable by 3 and 7.

In this way you can find out if the base is prime or not in one simple calculation!

Oh! Fair enough.

**Primenumbers**- Replies: 8

**Introduction**

The following is a way to find out if (a) is prime or not using Fermat's Little Theorem.

**Rule**

x=(All primes below square root a)-1, multiplied together. I.e. (2-1)(3-1)(5-1)(7-1)(11-1)....

a=any odd no.

**Theory**

Fermat's little theorem states that if p is a prime number, then for any integer a, the number

is an integer multiple of p.So if y=p-1 then will be factorable by p.

We know that remainders repeat themselves in a pattern when multiplying by a. So y could be a multiple of y and the answer would still be factorable by p.

In this way as long as x is factorable by p-1 then the answer will be factorable by p unless (a) itself is factorable by p.

**Example**

a=37

x=(2-1)(3-1)(5-1)=8

a=21

x=(2-1)(3-1)=2

** Conclusion**

I don't know but I would have thought this method would be useful for computers as it only requires a few computations. Don't computers usually have to factor possible factors separately? The numbers are very large though.

Okay bobbym. I am going to bed now. 6 o'clock in the morning where I am.

Night night.

Okay, that's fair.

My avatar is because I used to play judo.

I tend to do everything to the extreme also. My friends used to call me Xtreme when I was a bit younger because I used to do everything to the extreme. Jump off things, drink the most and drive stupidly, stuff like that. I have calmed down a lot now but still enjoy a good challenge! I am at a weird point in my life when I am finally feeling better and I just don't know what to do with myself.

Mmm....do many people die from sailing round the world?

bobbym wrote:

That she is a she.

What made you think I was a guy bobbym?

I have done some research in case anyone else is interested in climbing it.

It's going to set you back something like £40, 000.

You need to;

Go on a climbing course and then practice

Go on an ice climbing course and then climb a lesser mountain

Do a load of training before attempting the ascent

Also you should know;

70% of attempts are unsuccessful and for every 10 climbers that make the ascent 1 will die trying to

That is a high risk! I'm quite scared now..................................................... Oh well!

England.

The word 'Math' is invented. That's why you can say it in different languages and it doesn't matter. However the math itself was discovered because it is highly unlikely that some guy in China and some guy in England invented the same mathematics. They could have used different symbols.......... but it would have been the same mathematics.

If mathematics was invented to cope with sensory information linking it to reality. I would just like to say that all sensory information is real. Just because you could be dreaming doesn't mean you are.