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Hi bobby, got it, will try it in excel. thx. But still thinking what was wrong in my previous method.

Thanks

Hi anonimnystefy,

taking (y-y1) = m (x-x1) (m is slope)

for L1 : (y-0) = -7/5 (x-512)......A co-ordinates (512,0)

y = -7/5 x + 3584/5 ......

L2 : (y-0) = 2/6 (x-505).........C co-ordinates (505,0)

y = 2/6 x - 1010/6 .........

am I wrong ?

**No_Smart**- Replies: 5

Hi,

I am making a mistake while solving for intersection points of 2 lines :

There is Line L1 from A(512,0) to B(505,5). Another line L2 from C(505,0) to D(507,6)

So, Slope for, L1 = -7/5, L2 = 2/6

To get their intersection points i solve their equations :

Eq. L1 : y = -7/5x + 3584/5 (with point A)

Eq. L2 : y = 2/6 x - 1010/6 (with point C)

So, solving eq. gives me :

-7/5x + 3584/5 = 2/6 x - 1010/6

-42 x + 21504 = 10 x - 5050

52 x = 26554

x = 510.6

But, this is wrong answer (intersection point has to be between 505-507). I dont understand, where i am going wrong. I will be using the suggested method in Excel for futher calculations.

Thanks,

No Smart.

Hi, anonimnystefy, bob, ganesh, bobby, thx all for warm welcome.

**No_Smart**- Replies: 9

Hi all,

I am new to this forum and would like to introduce myself. My name is Raj & I am from India. Hope to share and learn from here.

Thanks,

Raj.

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