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#1 Re: Help Me ! » Need help with circumference and taper » 2012-03-15 23:29:58
How funny... worked that time! Kinda wish I had a CAD program now...
#2 Re: Help Me ! » Need help with circumference and taper » 2012-03-15 23:25:28
Thanks so much! Will try this today.
#3 Re: Help Me ! » Need help with circumference and taper » 2012-03-15 11:44:02
Never mind. I just tried again. It's just not working. I go to image upload, select one slot for image, select the image on my hard drive, click preview and nothing.
#4 Re: Help Me ! » Need help with circumference and taper » 2012-03-15 11:39:50
Oh I see now! I have to have at least 10 posts to be able to upload an image with my reply. This makes #10. I'll try in my next post!
#5 Re: Help Me ! » Need help with circumference and taper » 2012-03-15 11:35:08
I have the screen shot (I'm on a Mac), but I can't get it to post here in my reply. I did as you suggest, but it won't show...
I do appreciate the help SO much! Hey if you need any design work like business cards or invitations to something or whatever, let me know! THAT I can do!
PS
Tried again to upload screen shot jpg and it's not showing in preview.
#6 Re: Help Me ! » Need help with circumference and taper » 2012-03-15 09:10:23
I'm trying to include a screen shot of the tool I have to work with in Illustrator, but I can't seem to make it work on this forum. My IQ is dropping as we speak. Help?
#7 Re: Help Me ! » Need help with circumference and taper » 2012-03-15 08:42:02
Yes. The label is 1 inch from the bottom. I noticed, too, that when I create an arc in Illustrator, the ends jut out from the top and it makes it overwrap the pot. I need it to just barely overlap the ends as it wraps. If I try to squeeze it in from the sides, then my artwork distorts. I'm sure I can figure that on my end once I can get the formula down. Yes, I have access to Excel, although I don't know much about it since I work mostly with Adobe Creative Suite programs, being the artsy type. 
#8 Re: Help Me ! » Need help with circumference and taper » 2012-03-15 05:48:35
So much for that! We can't figure it out... 
Can you give me the solution in the numbers that I provided? I think if I have that, I might be able to figure out the next one on my own. Another figure you might need is that the label will be .75 from the top of the pot (which is 9.125 high), and the label is 7.375 tall. I need the percentage of arc and the slant. Sorry to be a pest!
#9 Re: Help Me ! » Need help with circumference and taper » 2012-03-14 02:08:12
I think I should be able to work out this formula from here... I may need a bit of assistance from a friend that knows a bit of trig, but this should do it! Thanks so much!
#10 Re: Help Me ! » Need help with circumference and taper » 2012-03-13 01:18:00
Bob - I thought I was smart - must be in other subjects. *sigh* I barely even made it through Algebra in high school, but #1 that was about 35 years ago, and #2 I thought it was because I didn't do my homework. Math for the most part is completely over my head. I did try writing down the formula on paper and made notes, to no avail. I hate to ask you to just tell me what it is, but at this point I have to. I'm kind of under the gun on this project, and they're in a hurry, so I need to get a sample of at least one completed today. If you could give me the numbers on this according to my measurements, I'm sure I can follow suit and determine the rest of pots of different sizes. Would you be willing? I'm an artist and make things look pretty. The synapses on the other side of my brain misfire when it comes to math! LOL
I think I got as far as determining R1=5.0625 (since the diameter of the large circle is 10.125) and R2=4.25 (since the diameter of the bottom of the pot is 8.5). Good so far, right? Then I divide the two? I get .84 (rounded off). What do I then do with that figure? I'm not sure exactly how to arrive at L. I know, I know, I didn't get very far.
Oh - the total height of the pot is 9.125, but the area the label will wrap around is 7.375
My other problem I just noticed is in order to create this "warp" or "arc" of the label in Illustrator, it only allows me to punch in a percentage, not a degree. Is that a problem?
#11 Re: Help Me ! » Need help with circumference and taper » 2012-03-12 11:24:16
Thanks for your responses! Bob, I'm not sure I understand any of that since I never took trig, but I have a fairly decent IQ so perhaps I can figure it out - I'd just need a bit of time. But yes, the diagram you show is what I have but flipped over. When the wrap is flat, it will have a curve and the outer end points will have a slant, which is what I'm trying to find. In Illustrator, I can use the warp tool to create and arc of a specified percentage, so I figure I can use that once I determine the correct formula to do so.
bobbym: The height of the pot itself is 9.125 but the height of the label will be 7.375 inches.
#12 Help Me ! » Need help with circumference and taper » 2012-03-12 09:01:50
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Let me start by saying I know absolutely nothing about trig, which I assume I would have to know to figure this out. I'm designing labels that wrap around a flower pot, but cannot figure out how to arrive at what percentage my warp or arc has to be. The pot is 31.5 inches at the top, 27.75 inches at the bottom (circumferences), and the label area will be 7.375 inches high. I have several other pots of varying sizes I'll need to create label wraps for. Is there a particular formula I could use to figure this out? Not sure if you need this, but the opening at the top is 10 inches, and the width across the bottom is 8.5 inches. Thanks so much!
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