Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 Re: Help Me ! » Permutation Generator » 2012-02-15 07:04:09

Hi many thanks for the reply.
I don't program .

#2 Re: Help Me ! » Permutation Generator » 2012-02-14 21:04:10

hello, l am looking at the first numbers you sent:
0  0  1
0  0  2
0  0  3
which were all 162 ways.

if l was to do the same for 1,2,3,4,5,6 how many ways will it be all together and can you also help me organise them please?
Many thanks

#3 Re: Help Me ! » Permutation Generator » 2012-02-14 10:40:31

Hi Bobbym
What you have send looks good.
l will change it round to suit what l need it for.
What formula did you use so that l can follow the same trend to organise larger number like 1,2,3,4,5,6,7,8,9,10?
Best regards

#4 Re: Help Me ! » Permutation Generator » 2012-02-14 10:18:43

Hi they are 1,2,3,4,5,6 on the vertical row and W D A on the horizontal row
what you did looks similar
Its like football pool games where 1,2,3,4,5,6 will be the teams

Eg will be


     W   D   A
1    x
2    x
3         x
4                x 
5         x
6                x
Many thanks

#5 Re: Help Me ! » Permutation Generator » 2012-02-14 07:26:35

Many thanks
The numbers am looking to perm will be like
W1,w2,w3,1d,2d,3d,1a,2a,3a
The table is like eg
    W.  D. A
1   X
2.  X
3.       X

Eg of this second table will be wrong
     W   D.  A
1
2
3. X.    X.   X

#6 Re: Help Me ! » Permutation Generator » 2012-02-13 10:33:02

Dear All
I need help on solving a problem .
I want to arrange numbers
Where there are three names on the vertical side like
  W.  D. A
1
2
3
I want to perm or combine where there are not more than one digit on the vertical role.

Eg.
   W. D. A

1. X
2. X
3. X
Or
   W. D. A
1  x
2.     X
3.          X

Any help please?
Many thanks

Board footer

Powered by FluxBB