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Dear googol

p should be a prime whereas p=35=5x7, p=51=3x17, p=341=11x31

Basically 0/0 can be anything. Unless we tend to go beyond normal understanding of infinity, we can actually get 0/0=1. For example

let

Taking natural long on both sides yields

Then

If we could consider the "undefined" cancelling each other equal to zero.

Thus

We can argue like forever with this thing but this is how mathematics progresses Perhaps 0/0=An Apple:)

If you have an equation of x=y, it is always passing through the coordinate {0,0}. Since,

it concludes that :)Extension into odd numbers instead of using primes

Where

Example

Extension into negative Primes

Example

The largest solution for

could be only whenYou get funny values when you take all the infinities as the same. Infinity as a concept gives rise to many problems like S=1-1+1-...infinity=1/2 because we tend to take all the infinities as the same like (1+infinity)=infinity. What is the value of infinity/infinity? I am more to the concept that the Infinity has an origin and point of reference. For example, if we had a source of light that could travel forever into the infinity and is set to travel today and the another one would be set to travel tomorrow, are they the same value when they reach infinity?

If they do have the same value, I can show you that Riemman zeta function

not and many more.**Stangerzv**- Replies: 0

Consider the equation below:

=Prime Sequencea=Square Root of without the decimal numbers

(A constant)

New Prime=

Where

Example:

Prime Sequence

2

3

5

7

11

13

17

19

23

Value of a

1

1

2

2

3

3

4

4

4

Value of b

1

2

1

3

2

4

1

3

7

New Prime

2

3

3

5

5

7

5

7

11

Another Larger Sequence

Prime Sequence

93703

93719

93739

93761

93763

93787

93809

Value of a

306

306

306

306

306

306

306

Value of b

67

83

103

125

127

151

173

New Prime

373

389

409

431

433

457

479

Perhaps there are lengthy new prime listing could be generated from the normal prime sequence.

Perfect Primes:

There are so far 3 groups of primes for consecutive power when n=3.

The list is given as follows:

For n<25, no apparent primes for Pt=5

For n<25, no apparent primes for Pt=6

For n<25, no apparent primes for Pt=7

Smallest solution for Pt=4, when n=3

Smallest solution for Pt=3, when n=2

Next prime when n=4

Next prime when n=6

Next prime when n=9

Next prime when n=15

Would there be primes at n=48?

From calculation n=48 would only give one prime