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#1 Re: Help Me ! » have a graph, looking for the function » 2005-11-04 01:48:50

ray

Thanks!

I have the solution now as:

if( (1-a) < (1-b) )

     r = 1 - ( (1-a) / (1-b) ) / 2;

else

     r = ( (1-b) / (1-a) ) / 2;

Ray

#2 Help Me ! » have a graph, looking for the function » 2005-11-03 13:37:23

ray
Replies: 2

Hi !

I am writing a 3D shader and I got this graph and I just can't figure out the function sad

function.jpg

The result value (given in greyscale values between 0=black and 1=white) depends on the two variables a and b.

It is for example,

0.5 when a=b
1 when a=1
0 when b=1
0.5+(a/2) when b=0
0.5+(b/2) when a=0

(is there a name for this kind of graph btw.?)

I think it must be a quite simple function.

Thanks in advanced for help smile
Ray

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