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Thank you very much.
also I don't know if the restriction has something to do with it: x >= -1/2
Thanks
But without graphing the equation I should be able to find the inverse - let me give you an example:
f(x) = 2x + 1
y = 2x + 1
switch x and y
x = 2y + 1
x - 1 = 2y
x - 1 / 2 = y
so the f-1(x) = x - 1 / 2
But for some reason I can't figure out how to do that with the problem that I have now.
Problem:
f(x) = x^2 + x when x >= -1/2
I know the basic way to find the inverse of a function, but for some reason I can't seem to figure out what I'm doing wrong with this problem. Here's were I was going with it:
f(x) is the same as y.
y = x^2 + x
switch x and y
x = y^2 + y
here's where I get stuck - I'm trying to solve for y, so do I move the y over or something else???
Thanks for you help.
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