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#1 Re: Help Me ! » Elementary Maths » 2010-10-19 09:42:37

I was also wondering about solving the problem that way. Would it also be better to assume that boys = girls = 136/2 = 68, so start testing pairs starting from the middle of the ordered pairs? (if this question happened to appear in a test where external aids like calculators and excel spreadsheets are not allowed)

#2 Help Me ! » Elementary Maths » 2010-10-19 03:47:23

Replies: 12

Is it possible to solve this question without the use of algebra?

"A class has 136 pupils. 5/8 of the boys and 3/4 of the girls wear glasses. There are 93 pupils who wear glasses. How many boys are there in the class?"

#3 Re: Help Me ! » IMPT: Probability Question » 2005-08-28 11:47:15

Thanks alot! Actually, I was in that dinner tongue

#4 Help Me ! » IMPT: Probability Question » 2005-08-27 22:40:18

Replies: 3

I just thought of this question:

There are 350 people attending a celebration dinner.
Seated at every table are 10 people (35 tables).
One of the event is a lucky draw with 35 prizes to be given out by drawing numbers electronically.

Assumptions (if necessary):
1) Nobody can get a prize twice.
2) Everybody stays until the end of the event.
3) The drawing of the numbers is fair.

1) What is the chance that a person gets a prize?
2) What is the chance that at least one person from a table gets a prize?
3) What is the chance that everybody from a table gets a prize?

Anybody can help me? Please show your working and answers clearly documented.

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