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never mind,

it doesnt have odd symmetry

## #2 Re: Help Me ! » Hyperbolic equation... » 2005-09-25 22:18:12

This setup

2A = (1+e^B)e^C + (1+e^(-B))e^(-C)

is similar to drift-diffusion in a transistor .

We couldn't get it into closed form unless we made some assumptions.

C1, MD/H and MR/H

like MR/H+C1  ≈ C1

this would be nice

## #3 Help Me ! » Exponential curve fit » 2005-09-24 16:31:28

Atled
Replies: 1

Anyone know how to do regression analysis of a shifted exponential curve.

here is the data

1    0.997706596
2    0.243081214
3    0.079426264
4    0.03319443
5    0.016202707
6    0.00969521
7    0.007108719
8    0.004852038
9    0.003415406
10    0.002462571
11    0.001977777

the equation should look like a^((-x+1)/b) i think.

I cant seem to do it with my calculator it doesn't handle the shift.

Thanks

## #4 Re: Help Me ! » Calculus » 2005-09-24 13:27:23

f(x)=  [(x^3) - 3(x^2) + 4]/x^2

divide through by x^2

you get

f(x) = x - 3 + 4x^(-2)

use the power rule  f(x) = x^n  f'(x) = n*x(n-1)

f'(x) = 1 - 8*x^(-3)

then factor out x^(-3)

[x^3 - 8]*x^(-3) =  [(x^3)-8]/x^3

## #5 Re: Help Me ! » Hyperbolic equation... » 2005-09-22 20:34:47

cosh(x) can be approximated with a taylor expansion.

its the same as the expansion for cosine

1  + x²/2 + x^4/ 24+ ....

## #6 Re: Help Me ! » extreem of function » 2005-09-14 08:47:13

1/4(2+Cos[2(a-b)]+Cos[2(a+b)]-2Cos[c]Sin[a]Sin)  <- something seems wrong here

Sin needs a variable.

if a = 0 b= pi/4

you get 1/2

but you might be able to get something smaller than that.

You might try taking partial derivatives of  Cos[2(a-b)]+Cos[2(a+b)] wrt a & b and look for extrema. You could also try to write an excel spread sheet which tries different combinations of a & b and use the goal seek function.

I am in a hurry but I will try to work on it later.

## #7 Re: Help Me ! » Simple Dot Product Question.. Please help, studying for quiz. » 2005-09-09 12:54:40

25/m/Ca

EE student at UC Davis

hobbies: cycling, skating, surfing although there are no oceans near davis

## #8 Re: Help Me ! » Simple Dot Product Question.. Please help, studying for quiz. » 2005-09-07 22:12:33

A . (A + 3B +7C) = A.A + 3(A.B) + 7(A.C)

A.B and A.C are given

A . (A + 3B +7C) = A.A +(3*3) +(7*-1)

A . (A + 3B +7C) = A.A + 2

whats A.A

X.Y = |X|*|Y| * cos(θ)

A is PARALLEL to A there for θ = 0

or

The angle between A and A is 0

cos(0) = 1

A.A = 4

A . (A + 3B +7C) = 4 + 2 =6

hope that helps

edit: previously i said normal

## #9 Re: Help Me ! » Integration. Where is the 2 coming from? » 2005-08-22 22:52:39

∫ ( ln(x)/x )  dx  or  ∫ (dx/x) *ln(x)

let u= ln(x)

du/dx = 1/x or du = dx/x

replace dx/x with du

and ln(x) with u

then you are left with ∫ u du == u²/2

thats where the 2 comes from.