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I have been waiting. There are 3 basic ways.
I can't handle either cases.
There are no such numbers besides x=5 and y=3.
The last digit can be done by mods. The first digit is usually just raw computation except in specific cases. The middle digits are like the first digit.
How did you calculate all this?
How many have you looked at?
Nearly. It is y^(xxxxxx). x and y are single-digit integers >0, and y may = x.
You mean of the type
As far as I know (after having done just one test like this), my example is unique and doesn't extend to other sums.