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- MathsIsFun
- 2005-05-09 22:46:34
Hmmm ... if you treat (A*e^c) as a constant, call it "f" then you have:
f t^b
which is easily differentiated as
f t^b ln(b)
(derivative of a^x = a^x ln a)
There may be something special with your formula that I am not aware of, though!
- tOmd
- 2005-05-09 21:45:55
How do I differentiate At^b * e^c?
Where t is the variable, e is euler's number and A, b and c are all constants. I'm pretty sure I should be able to be able to simplify it to t = b/c or something like that.
Please Help!!!