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- krassi_holmz
- 2006-03-09 04:50:31
for ashwil:
the probability is 5 seconds less than ganesh's. 
- lakitu
- 2006-03-09 04:29:32
thank you to both of you ! big help i understand it all
regards
lakitu
- ashwil
- 2006-03-09 03:48:06
mathsy, calculate the following:
What is the probability that ashwil will not only be able to answer an algebra/calculus question correctly, but will also be able to type & post his answer before ganesh, Ricky, krassi_holmz, yourself, mathisfun etc etc.?
I want my mummy!
- mathsyperson
- 2006-03-09 03:40:59
Hehe, don't worry, it happens to all of us. I was beaten by 3 seconds not too long ago.
But eventually, you're going to beat someone by a tiny amount as well, and the universe will be restored.
- ashwil
- 2006-03-09 02:52:47
Shucks! Beaten to it by 5 seconds!!
- ashwil
- 2006-03-09 02:51:24
If x = t+1, then rearranging gives t = x-1
We can then substitute (x-1) for t in the equation y = -3t² + 3t so that:
y = -3(x-1)² + 3(x-1)
Multiply out to give:
y = -3(x²-2x+1) + 3x -3
and further to give:
y = -3x² +6x -3 + 3x -3 = -3x² + 9x - 6
Factorising -3x² + 9x - 6 gives:
y = (-3x + 3)(x-2) OR -3(x-1)(x-2)
Solving for y=0 gives x= 1 or 2
- ganesh
- 2006-03-09 02:51:19
Since x=t+1, t=x-1.
Given
y=-3t²+3t
Therefore,
y=-3t(t+1)+6t
y=-3(x-1)(x)+6(x-1)
y=-3x²+3x+6x-6
y=-3x²+9x-6.
You can verify this by substituting x=t+1 in the Cartesian equation.
y=-3(t+1)²+9(t+1)-6
y=-3t²-6t-3+9t+9-6
y=-3t²+3t
This is the parametric equation of y given.
Hence, the Cartesian equation is correct. 
- lakitu
- 2006-03-09 02:48:52
hi again, i have re written my question in a better way, sorry for the confusion.
i have figured out how to do a simple parametric - cartesian equation in the form of x and y here is what i have already done.
x = 2 t - 2 -----------------(1)
y = 3 t - 2 -----------------(2)
multiply (1) by 3 and (2) by 2.
3x = 6 t - 6 -----------------(3)
2y = 6 t - 4 -----------------(4)
eliminate t from the two eqns by subtracting (4) from (3)
3x - 2y = -6 + 4
3x - 2y = -2
in my exam i am assured i will need to know harder ones like this, but i cannot figure out how to do these.
Express the parametric equations x = t + 1 and y = -3 t² + 3 t as a Cartesian equation in just x and y.
i also need to simpify this in the form y = a x² + b x + c.
Any help would be great.
kind regards lakitu
- lakitu
- 2006-03-09 02:15:54
hi apologise if this is in the wrong forum
my lecturer has told me that i need to be able to express parametric equations as a cartesian equation and then Simplify it into the form y = a x² + b x + c in my exam later this month. my mind boggles !
here is an example i have found.
Express the parametric equations x = t + 1 and y = -3 t² + 3 t as a Cartesian equation in just x and y.
any help would be great!
kind regards lakitu