I guess the question is finding the equation of a straight line whose slope is 2/5 and which passes through the point (-20, 9).

The equation of a straight line passing through a given point (x1, y1) and with a given slope, m, is

y - y1 = m(x - x1).

In the given problem, x1 = -20, y1=9 and m=2/5.

Therefore, the equation of the straight line is

y-9 = 2/5[(x+20)]

5y-45 = 2x + 40

5y - 2x = 85

2x - 5y + 85 = 0 is the required equation.