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Topic review (newest first)
You probably see your mistake now, you have typed - 1/h, when you mean - 1/a
Anchor, the very first definition of derivative means delta y divided by delta x, which means rise over run or slope.
Or, using the power rule:
[f(x)/g(x)]' = (f'(x)*g(x) - f(x)*g'(x))/[g(x)]^2 = (0*x - 1*1)/x^2 = -1/x^2
the problem gives the function of x as: f(x)= 1/x