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Yes, that's supposed to be the answer for the practice test. Since 'e' is the only one that is not true (supposedly), I am asumming a,b,c and d are true, that's why I considered those scenarios at once
I'm not sure what your doing there. Your making both conditions true at once. You should only be considering each scenario individually. Not both at once.
Thanks a lot for your help you all. Maybe 'e' is not even the right question, I tried what some of you did, assuming a,b,c and d where right and using thos values in the equation but there seems to be something wrong:
perhaps, but most of those answers other then e produce fractional apples. Hmmm... frapples?
math_2778 probably said e because;
I did the same thing. Then I started plugging the values in and lo and behold the solution. But what I'm wondering is math_2778 said the answer is supposed to be e as if that were the book's answer. We'll see when he gets back.
Nice mikau! I know what I did wrong now. I tried to solve the problem with just the "problem" stated. I didn't even try to plug in the solutions. Lunkhead!
whoah! I think I got it. But its not e. Its d.
Don't feel bad mikau, I couldn't solve this one either. Missing information? I tried the constant rate scenario and got numerical results, but they did not agree with the stipulated parameters. For example; If John consitently picked 5/3 what Mark picked he would end up with 65 of the 104 total picked and Mark would be left with 39. So the constant rate possiblity is definitely out.
Well you got me. I can derive 3 equations from that and there are six variables. The problem is it gives no relationship about the apples they picked in the afternoon. Perhaps you can't actually solve it, but you can use the relationships to prove if a certain condition is not possible.
I need help with the following problem, I know it should be easier but for some reason I cannot get the right answer. I know the answer (It's supposed to be 'e') but I need the explanation of the process: