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No calculator needed thanks to a lesson given by Mathsyperson earlier in this forum. In any factorizable quadratic we can break up the b constant into two terms.
1) It's (8x - 3)(8x + 3).
Do five out six, including Q2 and / or Q5. The problems that involve finding a solution (Q2, Q4, Q5) are to be done algebraically - by setting up and solving an equation. The object of Q2, for example, is not to 'play with' various consecutive-integer combinations until coming up with the solution (which is five and six) but to decide what the 'unknown' (x, say) should represent, and: (1) develop an equation that involves the unknown and utilizes the information provided; and then (2) solve that equation algebraically – demonstrating that five and six are a solution by 'plugging in' these values into the equation is not solving it. Please show all work / explain your answers.