Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

• Index
•  » Help Me !
•  » How do you get the secant and cosecant intergration formulas?

## Post a reply

Write your message and submit
|
Options

## Topic review (newest first)

irspow
2006-02-12 06:36:07

Mikau is correct.  Besides if you just integrate sec x = 1 / cos x

∫1 / cosx  dx = ln[cos(x/2) + sin(x/2)] - ln[cos(x/2) - sin(x/2)] + C

It is much neater to use their solution.

mikau
2006-02-12 06:06:29

Basicly we begin with sec x. We multiply above and below by sec x + tan x to get:

( sec^2 x + sec x tan x  )/ (sec x + tan x )

if we let u = sec x + tan x, we can differentiate to find du = sec^2 x + sec x tan x   which happens to be the expression in the numerator, therefore we make the substitutions to get:

1/u du

this is the derivative of ln u. So the answer is ln|u|. We declared u to be sec x + tan x therefore the answer is ln|sec x + tan x|  and of course, + C.

Basicly muliplying above and below by sec x + tan x is a nifty trick that gives it the form 1/u du which is easy to integrate.

irspow
2006-02-12 05:02:39

They did say it isn't intuitive...I really don't know.  They might have chosen that identity simply for ease of simplification after integration.  I am in no way a proofs guy.

fatulant
2006-02-12 04:52:33

why multiply by sec x + tan x?  Why not sin x + cos x?  Or csc x + cot x?

irspow
2006-02-12 01:00:19

What you are looking for can be found here:

www.math2.org/math/integrals/more/sec.htm

They say it isn't intuitive...and it isn't, but it is the proof.

flatulant guest
2006-02-11 11:43:20

I do not understand how the integral of secant x is ln(secant x + tangent x)+C and how the integral of cosecant x is -ln(cosecant x + cotangent x).  Can someone please explain to me how these are derived?

## Board footer

Powered by FluxBB