Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

Login

Username

Password

Not registered yet?

  • Index
  •  » Help Me !
  •  » Can anyone show me how to graph this please...

Post a reply

Go back

Write your message and submit
:) :| :( :D :o ;) :/ :P :lol: :mad: :rolleyes: :cool: | :dizzy :eek :kiss :roflol :rolleyes :shame :down :up :touched :sleep :wave :swear :tongue :what :faint :dunno
Options

Go back

Topic review (newest first)

mathsyperson
2006-01-22 08:55:47

I'd have just said x∈R, x≠-1. But everything's still right though. Well done.

irspow
2006-01-22 08:34:13

Sorry, I forgot about the domain.

The domain is the range of values of x that give a real value of y.

The only time this function would not do so is when the denominator was zero, because division by zero is not allowed.

This only happens when x = -1;

So the range would be -∞≤x<-1, -1<x≤∞

irspow
2006-01-22 08:24:51

The x-intercept occurs when y = 0;

0 = (3x+2)/(x+1);

This is only true when 3x+2=0 or x = -2/3

  Similarly the y-intercept occurs when x = 0;

(3x+2)/(x+1) when x = 0 becomes 2/1 or 2

A horizontal asymptote occurs when the functions has a limit as x approaches infinity.

If you divide the numerator and the denominator by the highest power of x in this question you get;

y = (3 + 2/x) / (1 + 1/x)

if you let x approach infinity then;

y = 3/1 or 3

katy
2006-01-22 08:11:27

How can you change this to descriptive form, graph it and state the Domain, HA(Asymptote), Y-intercept and X-intercept??Please give me a tutorial!

y=(3x+2)/(x+1)


thanks a lot.....yikes

Board footer

Powered by FluxBB