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Topic review (newest first)
incase your not sure where I got the requirements from. If you have an expression such as |x + 1| if the value of x + 1 is less then zero, it will be negative. Therefore, if x + 1 is less then 1, the expression will haves its sign changed. Thus |x + 1| equals -(x + 1) when the expression is less then 1. To find when x + 1 is less then zero: x + 1 < 0 solved x < -1. Lets try a value less then -1 as a test. |-2 + 1| = 1. But -2 is less then 1 so instead of | x + 1| we can write -( x + 1) x = -2 so
doesn't look easy at all. Absolute value algebra is a nightmare!
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