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jacs
2006-01-17 10:42:37

thank you thankyou thankyou  I see it now.... i had the negative log and so cheated assuming that the 3Q was 300 instead of 900 (which i secretly knew was wrong...lol....but coudnt get rid of negative log so sort fudged the results)

what i needed was just the clever maniplutaion of the minus...ohhh soo easy now i see

thanks

jacs

MathsIsFun
2006-01-17 08:51:00

Nice work, Ricky!

#### jacs wrote:

Show that the quantity of salt, Q gram, in the tank at any time t is given by:
Q = 200 + 100e-0.03t

And, of course, the 100e-0.03t term decreases with t, so it should be added.

Ricky
2006-01-17 03:11:27

You use a different method for solving differential equations than I'm used to, and quite an awkward one at that.  See if you can follow this, and if you want, I can try to find the error in your steps.

Integrate both sides

jacs
2006-01-17 00:57:29

Hi, my first post, and i need help with some applications of calculus to physics

A tank contains 100 litres of brine whose concentration is 3 grams/litres. Three litres of brine whose concentration is 2 grams/litre flow into the tank each minute and at the same time 3 litres of mixture flow out each minute.

Show that the quantity of salt, Q gram, in the tank at any time t is given by:
Q = 200 + 100e-0.03t

i have managed to get Q = 200 - 100e-0.03t

and cannot figure out why the minus is there, i have included the pdf of the working i have done so far, any help appreciated

thanks
jacs