Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

Login

Username

Password

Not registered yet?

Post a reply

Go back

Write your message and submit
:) :| :( :D :o ;) :/ :P :lol: :mad: :rolleyes: :cool: | :dizzy :eek :kiss :roflol :rolleyes :shame :down :up :touched :sleep :wave :swear :tongue :what :faint :dunno
Options

Go back

Topic review (newest first)

mikau
2006-01-08 17:31:07

If you really can't get it I'll explain how to do it, but you really ought to learn to do this for yourself.  I wouldn't really be helping you if I just did the problem for you.

mikau
2006-01-08 10:03:08

Also note the identiy for sin(2x) and the three identities for cos(2x).

I'd really really really reccomend printing out a reference sheet of all the indentities. I have a binder of lots of difference indentities and math notes. This is math, not spelling. Understanding why a formula works is more important then remembering it. Just print out a reference sheet.

mikau
2006-01-08 10:00:11

I could work it out myself but I think you should.

First I'd suggest replacing cos(3x) and sin(3x) with cos(2x + x) and sin(2x + x) then use the sum identities. We did this in the previous example. And note the identity tan (2x) = (2 tan x)/(1 - tan^2 (x) ). Also note that tan x = (sin x)/(cos x)

You can do it!

number0001
2006-01-08 09:46:35

I got another trig problem, which is to prove (make the left side of the "=" equal to the right side).

(cos3x-cosx)/(sin3x-sinx)=-tan2x

I tried it but got stuck. Thanks very much for any help!

Board footer

Powered by FluxBB