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Topic review (newest first)
And here's a plot
Here is it in Mathematica language:
Yes, I saw that. My first result:
Be careful, though. As we can see from the example above, how many prime factors a number has isn't the only thing it depends on.
I thought out an algoritm that can be used
Wow! Thank you for your help!
If n is product of two prime we have 2 combinations:
If n is prime we have only 1 combination:
Can we find formula for this?
you're absolutey right!
There are a few more combinations for 56 and 100, because 8 and 4 can be broken down more.
you're absolutely right!
Let there be x cubes. the volume of each is 1.2^3=1.728 =>