1. General form of a parabola equation is: (y-k)=a*(x-h)^2 where (h,k) is the vertex and a is a scale factor.

That gives y+1 = a*(x+4)^2

Since (0,-5) works for the equation, substitute and solve for a:

-5 + 1 = a*(0+4)^2

-4 = a*16

a = -1/4

so your equation is:

y + 1 = -1/4 * (x+4)^2

2. Let x be one number and (x-10) be the other number...

So you want to minimize x*(x-10), which is x^2 - 10*x. The lowest point is at the vertex, so the

x coordinate of the vertex is one number, and your other number is x-10.

Vertex occurs at -b/2a = 10/2 = 5, so the two numbers are 5 and -5