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  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

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Topic review (newest first)

austin81
2005-12-24 01:49:59

I'm not very sure of that.

austin81
2005-12-24 01:48:15

In my opinion I do think (x,y,z) = [z - g(x,y)]/3 is coorect.Since we shall be integrating

Flowers4Carlos
2005-12-20 21:11:46

i have a quick question regarding the unit normal vector on the following integral:

∫∫FdS = ∫∫FndS
s             s

if the surface S is given by z=g(x,y) then the unit normal vector is f(x,y,z)= z - g(x,y)  ⇒

       gradf(x,y,z)
n= -----------------
      |gradf(x,y,z)|

my question is if i'm given the surface 3z=g(x,y), then what should the unit normal vector be???

is it f(x,y,z) = 3z - g(x,y)     or     f(x,y,z) = z - g(x,y)/3

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