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- austin81
- 2005-12-24 01:49:59
I'm not very sure of that.
- austin81
- 2005-12-24 01:48:15
In my opinion I do think (x,y,z) = [z - g(x,y)]/3 is coorect.Since we shall be integrating
- Flowers4Carlos
- 2005-12-20 21:11:46
i have a quick question regarding the unit normal vector on the following integral:
∫∫F•dS = ∫∫F•ndS
s s
if the surface S is given by z=g(x,y) then the unit normal vector is f(x,y,z)= z - g(x,y) ⇒
gradf(x,y,z)
n= -----------------
|gradf(x,y,z)|
my question is if i'm given the surface 3z=g(x,y), then what should the unit normal vector be???
is it f(x,y,z) = 3z - g(x,y) or f(x,y,z) = z - g(x,y)/3