Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
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True. That method wouldn't work if the range had a number of the form (n+0.5)π in it, because the sign changes at every point with that form, but they are not roots.
Just don't forget to also state the function is continuous from [1.1, 1.2].
To show that there is a root between 1.1 and 1.2, just find the values of the functions at each of those points and show that there is a change of sign.
i was working on problem one in degree mode and my calculator kept spitting out positiive results even for very large values of x. then i switched over to radian mode and it worked! sometimes a lil trial and error will get you on the right track!
The first one is 1.165561185 and then my little solar calculator couldn't go any further. It took six iterations using Newton's Method.
I have this mathematics question that is really giving me a headache.......