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  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

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Topic review (newest first)

mathsyperson
2005-12-06 02:13:11

Correct, but you've missed out some possible solutions.

π/12, 5π/12, 3π/4, 13π/12, 17π/12 and 7π/4 all work.

krassi_holmz
2005-12-05 17:20:46

2sin3xcos3x=2(sin6x)/2=sin6x, so
sin6x=1
x = (1/6)(Pi/2)=Pi/12

runnerboy16
2005-12-05 15:57:28

thanks, but that isnt what i need.

Ricky
2005-12-05 15:47:25

http://aleph0.clarku.edu/~djoyce/java/trig/identities.html

Use the product identity, about 3/4th the way down the page.

runnerboy16
2005-12-05 15:32:33

I need to know how to find all the solutions for the problem- 2sin3xcos3x=1   within the restrictions of [0,2pie)

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