"1. If m+2=0;m=2
0x=-2
No solution"
Not true. Let m = 2, then you get the equations: 2x + y = 2, so y = -2x + 2, and y = 2x + 4. A common solution to these is the point (-1/2, 3).
"2. 2. If m+2≠0;m≠2
x=-2/(m+2)
So:
No solution-
m=2
One solution-
m≠2"
The logic here is right, if m = 2 had no solutions, than all lines without that slope intersect the line. Unforutunately, m = 2 has a solution.
"Infinite many solutions-
m∈{}"
Correct. The x-intercepts are off, and they only thing you can change is the slope.