Ah, so you did mean a slope of -3/2 after all.

"y= -1.5x - 6"

Try plugging in the point (2, -3) into this. That would be: -3 = -1.5 * 2 - 6, so -3 = -9. That is, of course, wrong. The line can't possibly pass through that point.

It's much easier way to do this problem is called point-slope form. That is, it's the equation that occurs naturally when you have a point and a slope, and you want to form a line (exactly what you have ).

The form is: Slope: m, point: (x1, y1), equation: (y - y1) = m(x - x1). So inputing your values, m = -3/2, x1 = 2, and y1 = -3, you get:

(y - (-3) ) = -3/2 * (x - (2) ), which is y = -3/2x + 3 - 3, which is y = -3/2x. This can then become 2y = -3x, and so 3x + 2y = 0.

No visualization required.