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- ganesh
- 2005-12-03 20:56:52
mathsyperson wrote:
Viny did say we could use whatever math[s] possible.
Okay, what about 4->6->8->9? This is geater than Graham's Number! 
(-> is chained arrow notation of John Conway)
- mathsyperson
- 2005-12-03 20:52:07
For the 4!!!!!, you'd need to use brackets to show what you meant.
4!! just means 4*2. 5!! is 5*3*1, and so on.
Double-factorials are less than their single-factorial counterparts (except with 0, 1 and 2)
MathsIsFun wrote:
But that may be cheating...
Viny did say we could use whatever math[s] possible.
I think Flowers4Carlos's version would be higher, but that's just a guess.
- ganesh
- 2005-12-03 20:51:02
- MathsIsFun
- 2005-12-03 17:01:33
Ginormous numbers. Good link Ganesh.
Conclusion: we need to set a limit on the operators then, or you could just use 4^^^^^..., or even 4!!!!...
- ganesh
- 2005-12-03 15:47:55
I think 4^^^6^^^8^^^9 is a much bigger number. You can use any number of '^' and keep increasing the number. There's no end to it.
If you are interested in knowing what x^^^y or x^^^^y is, go to this page.
- MathsIsFun
- 2005-12-03 15:30:36
Haha, both with similar idea!
- MathsIsFun
- 2005-12-03 15:29:06
Sorry, had to remove your address for "internet safety" reasons.
9864! (that is 9864 factorial ... 70! has about 100 digits, 9864! will possibly have tens of thouands of digits)
But that may be cheating ...
- Flowers4Carlos
- 2005-12-03 15:26:04
uh oh! you are not allowed to post your email. you gotta send in your birth certificate to rod proving you are of a certain age first 
and as for your query.... i guess it would be (4!)^(6!)^(8!)^(9!)
my calculator can't even handel 2^9!
- Viny
- 2005-12-03 14:37:34
Please help me, Someone asked me what is the BIGGEST value to put these four numbers ( 4; 6; 8; and 9 )together, use whatever math posible.
Please answer to my email address : [snip]
Thanks a million