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ganesh
2005-12-03 20:56:52

mathsyperson wrote:

Viny did say we could use whatever math[s] possible.

Okay, what about 4->6->8->9? This is geater than Graham's Number!

(-> is chained arrow notation of John Conway)

mathsyperson
2005-12-03 20:52:07

For the 4!!!!!, you'd need to use brackets to show what you meant.

4!! just means 4*2. 5!! is 5*3*1, and so on.

Double-factorials are less than their single-factorial counterparts (except with 0, 1 and 2)

MathsIsFun wrote:

But that may be cheating...

Viny did say we could use whatever math[s] possible.

I think Flowers4Carlos's version would be higher, but that's just a guess.

ganesh
2005-12-03 20:51:02

MathsIsFun
2005-12-03 17:01:33

Conclusion: we need to set a limit on the operators then, or you could just use 4^^^^^..., or even 4!!!!...

ganesh
2005-12-03 15:47:55

I think 4^^^6^^^8^^^9 is a much bigger number. You can use any number of '^' and keep increasing the number. There's no end to it.
If you are interested in knowing what x^^^y or x^^^^y is, go to this page.

MathsIsFun
2005-12-03 15:30:36

Haha, both with similar idea!

MathsIsFun
2005-12-03 15:29:06

9864! (that is 9864 factorial ... 70! has about 100 digits, 9864! will possibly have tens of thouands of digits)

But that may be cheating ...

Flowers4Carlos
2005-12-03 15:26:04

uh oh!  you are not allowed to post your email.  you gotta send in your birth certificate to rod proving you are of a certain age first

and as for your query.... i guess it would be (4!)^(6!)^(8!)^(9!)

my calculator can't even handel 2^9!

Viny
2005-12-03 14:37:34

Please help me, Someone asked me what is the BIGGEST value to put these four numbers ( 4;  6;  8;  and 9 )together, use whatever math posible.