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  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

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Topic review (newest first)

mathsyperson
2005-11-29 05:08:15

That would work. -[2x² + 3x - 2] factorises to give -(x+2)(2x-1).

RickyOswaldIOW
2005-11-29 04:21:53

Okay, maybe I should not take the 2 from the x^2 and instead have;

-[2x^2 + 3x - 2].

I think this will work but I have to go out now, thanks anyway smile

RickyOswaldIOW
2005-11-29 04:18:02

Factorising quadratics that is;

I have y = 2 - 3x - 2x^2.

Normally I would take out the coefficient of x^2 and thus have;

y = -2[x^2 + 1(1/2) - 1]

But I can't seem to factorise this?...

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