Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
You are not logged in.
Post a reply
Topic review (newest first)
- mathsyperson
- 2005-11-29 05:08:15
That would work. -[2x² + 3x - 2] factorises to give -(x+2)(2x-1).
- RickyOswaldIOW
- 2005-11-29 04:21:53
Okay, maybe I should not take the 2 from the x^2 and instead have;
-[2x^2 + 3x - 2].
I think this will work but I have to go out now, thanks anyway 
- RickyOswaldIOW
- 2005-11-29 04:18:02
Factorising quadratics that is;
I have y = 2 - 3x - 2x^2.
Normally I would take out the coefficient of x^2 and thus have;
y = -2[x^2 + 1(1/2) - 1]
But I can't seem to factorise this?...