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1 inch stone reaches terminal velocity at about 23.93m/s (m=18.9g)
Hi irspow. Good posts. Would you like to become a Member?
Ooh, ganesh missed the initial velocity as well. He even said 'u=0'. He must have been having an off day.
Actually, Ganesh forgot about the initial velocity that the stone was thrown.
623.097 ft @ 5s
I think ganesh forgot about the '/2' bit in his formula, so got the distance travelled in A double what it should have been, and that error carried forward into B.
Thanks, I got the answer though.
S = ut + at²/2, u=0
A stone is thrown straight down from the edge of a roof, 1050 feet above the ground, at a speed of 5 feet per second.