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Post the problem and who knows.
Later I need help on the solution to a problem that they were working on last night and I don't agree that their answer is right.
That is correct! Very good. M was nice to me there.
The plugging in part was not the best idea.
I will send you all the literature I have on this type problem.
I see that now. So wonderful how they figured it out.
The exact chronology I do not know. Huygen reformulated Pascal - Fermat's work.
where i is the amount Maria starts with i = 10 bets. n = ∞ which means Maria never goes broke even in an infinite number of plays. p = 2 / 3.
Plugging in we get:
So Maria has a 99.90234375% chance of winning indefinitely and a .09765625% chance of going broke.
It has been known since the time of Huygen that if Maria and Sam both have the same percentage of winning then she is sure to go broke. But that is not the case here because Maria has a better chance of winning each bet.
Sam and Maria are playing a game where a dice is rolled. If it lands a 1 or a 2, Sam wins $10 off Maria. If the dice lands a 3,4,5 or 6, Maria wins $10 off Sam.