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Please tell me how did you get that?
That is what I mean, the numerator is only equal to the denominator when a=b=c.
When a,b,c>0 it is easy to prove that fraction is greater than 1 therefore there can be no sin(θ).
This is equal to,
There is only equality when a=b=c which violates the given conditions. That completes the proof for a,b,c>=0
Or use the AMGM.
Now add up the 3 inequalities and divide by 2 and the result follows. There is only equality when a=b=c.
They are distinct.
You can find solutions if a = b.
I do not think so.
I would also say no, because if it was yes Suman Sir would not have asked it.
Is it possible that
Where a, b and c are distinct real numbers.