Two lines are perpendicular if the product of their gradients equals -1 Write each equation in the form y=mx+c: where m is the gradient. px+4y-2=0 y=-(p/4)x+1/2......., m1=-p/4 2x-y+p=0 y=2x+p.........., m2=2 m1*m2=-1...., (-p/4)*2=-1....p=2
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the lines px + 4y - 2 = 0 and 2x - y + p = 0 are perpendicular. Find the value of p.
The lines x+2y+12=0, x-2y+3=0, 2y+x-8=0 and x-2y-2=0 form a quadrilateral. What is the best description for this quadrilateral?