hi Equation_Kitty,

Welcome to the forum.

To avoid confusion between your posts and Derick Mixon's thread, I've moved your question here in it's own thread.

[If you click on the Help Me link you'll see you can start your own new topic by clicking the 'Post New Topic' link on the right.]

Now to think about an answer.

Yes, what you have said is OK, as long as x ∈ {reals}

There's a larger set called {complex numbers} in which square roots of negative numbers exist. As you specified {integers} your argument is OK.

There's probably a way to write this out rigorously if that is what is required.

Bob