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bob bundy
2013-09-12 17:09:11

hi Equation_Kitty,

Welcome to the forum.

[If you click on the Help Me link you'll see you can start your own new topic by clicking the 'Post New Topic' link on the right.]

Yes, what you have said is OK, as long as x ∈ {reals}

There's a larger set called {complex numbers} in which square roots of negative numbers exist.  As you specified {integers} your argument is OK.

There's probably a way to write this out rigorously if that is what is required.

Bob

bob bundy
2013-09-12 16:58:46

I have moved this post for Equation_Kitty.

Hi all!! I'm super new to Math is fun forum. I stumbled onto here while researching how to prove x² ≥  0‎. I need help with this proof I know it's very basic. I need someone to show me the light!

could you simply say "for x² ≥ 0 ‎based on the non-negative property of squares, a square of a number will always be greater ‎than or equal to zero. ‎Thus x² ≥ 0‎ is true for all integers...?

Bob