Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

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Topic review (newest first)

kylekatarn
2005-11-20 07:36:43

He hasn't complained yet smile

zhaobin
2005-11-20 07:15:21

I think he mean |a|<1

kylekatarn
2005-11-20 02:54:16

Let a ∈ ℝ. Accoding to you condition,  |a|<0, we can build the set:
A = {a ∈ ℝ : |a|<0}
From the definition of absolute value, we conclude that A = ∅. So with |a|<0...."there's nothing left to prove". : )

Barak
2005-11-20 01:18:26

Question:

prove that if |a|<0 then
  lim    n(a^n) = 0
n-> ∞

please give me a hint or an explaination to how to solve this problem.
:-)

Barak

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