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Topic review (newest first)
- kylekatarn
- 2005-11-20 07:36:43
He hasn't complained yet 
- zhaobin
- 2005-11-20 07:15:21
I think he mean |a|<1
- kylekatarn
- 2005-11-20 02:54:16
Let a ∈ ℝ. Accoding to you condition, |a|<0, we can build the set:
A = {a ∈ ℝ : |a|<0}
From the definition of absolute value, we conclude that A = ∅. So with |a|<0...."there's nothing left to prove". : )
- Barak
- 2005-11-20 01:18:26
Question:
prove that if |a|<0 then
lim n(a^n) = 0
n-> ∞
please give me a hint or an explaination to how to solve this problem.
:-)
Barak