Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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## Topic review (newest first)

Agnishom
2013-08-20 17:48:19

:d

bob bundy
2013-08-20 17:16:11

All over the denominator like this:

Then put the first three into a 'perfect square'.

Bob

Agnishom
2013-08-20 13:56:33

#### bob bundy wrote:

add and subtract the term

Like this?

Agnishom
2013-08-20 13:50:39

Sorry for my late reply.

I will do these as soon as possible

bob bundy
2013-08-20 00:08:33

I may have gone 'round the houses' to do the second, but it works.  In other words, some steps may be eliminated I think.

exercise for you: do a similar thing with b^3

evaluate a/b and b/a and substitute all into (1)

everything cancels leaving just a 1

Bob

bob bundy
2013-08-19 23:42:48

cancel and put over common denominator

add and subtract the term

make use of

Bob

stereogram answer on the other thread

Agnishom
2013-08-19 22:39:22

Thanks but I know these Identities. Yet, I am not being able to solve that at all. Please help me out.

I had almost forgotten about the stereograms. What did you figure out about it?

bob bundy
2013-08-19 16:55:51

hi Agnishom,

Starting with

That looks like a good way to start with those denominators.  Then put everything in terms of sin and cos in order to simplify.

The second identity looks somewhat tougher.  I'll come back if I make progress.

Bob

ps.  I've made some progress with stereograms.

Agnishom
2013-08-19 12:49:05

Prove these:

1.

2. If cosec  θ - sin  θ = a3 and sec  θ - cos  θ = b3, Then prove that: a²b²(a² + b²) = 1

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