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Topic review (newest first)
All over the denominator like this:
Then put the first three into a 'perfect square'.
Sorry for my late reply.
I may have gone 'round the houses' to do the second, but it works. In other words, some steps may be eliminated I think.
exercise for you: do a similar thing with b^3
evaluate a/b and b/a and substitute all into (1)
everything cancels leaving just a 1
cancel and put over common denominator
add and subtract the term
make use of
stereogram answer on the other thread
Thanks but I know these Identities. Yet, I am not being able to solve that at all. Please help me out.
That looks like a good way to start with those denominators. Then put everything in terms of sin and cos in order to simplify.
The second identity looks somewhat tougher. I'll come back if I make progress.
ps. I've made some progress with stereograms.
2. If cosec θ - sin θ = a3 and sec θ - cos θ = b3, Then prove that: a²b²(a² + b²) = 1