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Topic review (newest first)
Actually the constant C is not necessarily 0 in this case. True, velocity is 0 at t=0, but the C of integration of the velocity function represents the inital position of the particle at t=0. This was not specifically stated in the question.
v = 5t²+2t
Hi all, im new here and desparately need some help, itl probably be tooe asy for you guys, but i just cant seem to find the solution, so here goes...