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Okay, well, thank you very much, both of you, that's all i needed
Someone who supplied me with a different way of solving the problem. I wanted to mention him because he did not get the credit he deserved.
Who is blank?
Bobbym that's fantastic, thank you!
Definitely Thanks a lot
That's no problem, I'm not in a rush
Will post it as soon as I compute them. Please have patience it is a big calculation and will take a long time.
bobbym you're a star, that'd be fantastic, thanks a lot
Sorry, to quote:
I can't see what to do with this, either, but I suppose you could incorporate the expected total number of collisions into your calculation, along with the probability of two collisions already calculated. I just don't know how you would do that. If you know of a computer model, though, I'd be very happy just to have a numerical answer, I can understand that it would be very difficult to calculate this algebraically
That formula is for the expected number of collisions as far as I know, not the probability.
I think his suggestion was about 3 & 4, yes.
Where n is the number of people in the group, k is the range of days (so k = 7 in the case where I'm trying to calculate the number of people required in the group for me to be certain that two of them have birthdays within a week of each other) and m = 365 (the number of days, excluding the 29th of February.)
Using this, I was able to get the same answers as you
I'm completely stuck on 3 & 4, though. I can understand that there isn't an algebraic solution to this problem, but is there a numerical one? The only advice i've been given is to try and make use of that formula, but I wouldn't know what to do with it!